Study on the total number of valence electrons of ethyl acetate
Molecular Structure Analysis
Ethyl acetate, its chemical formula is\ (C_ {4} H_ {8} O_ {2}\). To find the total number of valence electrons, it is necessary to clarify the valence electron status of each atom. Carbon (C) is located in Group IVA of the Periodic Table, and each carbon atom has 4 valence electrons; hydrogen (H) is in Group IIA, and each hydrogen atom contains 1 valence electron; oxygen (O) is in Group VIA, and each oxygen atom has 6 valence electrons.

Calculation of the total number of valence electrons
1. ** Number of valence electrons contributed by carbon atoms **: There are 4 carbon atoms in the molecule, so the total number of valence electrons provided by carbon atoms is\ (4\ times4 = 16\).
2. ** Number of valence electrons contributed by hydrogen atoms **: 8 hydrogen atoms, the total number of valence electrons provided by hydrogen atoms is\ (8\ times1 = 8\).
3. ** Number of valence electrons contributed by oxygen atoms **: 2 oxygen atoms, the total number of valence electrons provided by oxygen atoms is\ (2\ times6 = 12\).

By adding up the number of valence electrons contributed by each atom, the total number of valence electrons of ethyl acetate is\ (16 + 8 + 12 = 36\).

In summary, the total number of valence electrons of each atom in ethyl acetate molecule is determined to be 36. This result is of great significance for in-depth understanding of the chemical properties of ethyl acetate molecule and related chemical reaction mechanisms.