On the Molecular Weight of Anhydrous Sodium Acetate
To study the molecular weight of anhydrous sodium acetate is an important matter for chemical research. To observe the composition of anhydrous sodium acetate, which is composed of sodium (Na), carbon (C), hydrogen (H), and oxygen (O) elements.

Sodium has an atomic weight of about 23. The atomic weight of carbon is about 12, the atomic weight of hydrogen is about 1, and the atomic weight of oxygen is about 16. The chemical formula of anhydrous sodium acetate is\ (C_ {2} H_ {3} NaO_ {2}\).

To find its molecular weight, according to chemical principles, each atomic weight should be counted according to its atomic number. In this chemical formula, carbon has two atoms, hydrogen has three atoms, sodium has one atom, and oxygen has two atoms.

Then the molecular weight of anhydrous sodium acetate is:\ (2\ times12 + 3\ times1 + 23 + 2\ times16\)
\ (= 24 + 3 + 23 + 32\)
\ (= 82\).

From this point of view, after rigorous calculation and analysis, the molecular weight of anhydrous sodium acetate can be obtained to be 82. This value is crucial in many fields of chemical experiments and industrial production, and can provide accurate data basis for related operations.