The reaction equation of potassium hydroxide with acetic acid
Potassium hydroxide ($KOH $) and acetic acid ($CH_ {3} COOH $) are neutralized, and the chemical equation is as follows:

$KOH + CH_ {3} COOH\ longrightarrow CH_ {3} COOK + H_ {2} O $

In this reaction, potassium hydroxide is a strong base, and potassium ions ($K ^ {+} $) and hydroxide ions ($OH ^{-}$）； acetic acid are weak acids, and hydrogen ions ($H ^ {+} $) and acetate ions ($CH_ {3} COO ^{-}$）。 Hydroxide ions combine with hydrogen ions to form water, which prompts the ionization balance of acetic acid to move forward continuously, and finally completely reacts to form potassium acetate ($CH_ {3} COOK $) and water. From the perspective of ionic reaction, the ionic equation of this reaction is:

$OH ^{-} + CH_ {3} COOH\ longrightarrow CH_ {3} COO ^{-} + H_ {2} O $

When writing chemical equations and ionic equations, it should be noted that acetic acid, as a weak acid, cannot be written in ionic form when writing ionic equations, while potassium hydroxide and potassium acetate, as strong electrolytes, are completely ionized in aqueous solution and can be written in ionic form.