The ionic reaction of acetic acid and potassium hydroxide
Acetic acid ($CH_ {3} COOH $) is a weak acid, partially ionized in solution, and potassium hydroxide ($KOH $) is a strong base, completely ionized in solution. Neutralization occurs between the two, and the chemical equation is $CH_ {3} COOH + KOH = CH_ {3} COOK + H_ {2} O $. When

is rewritten as an ionic equation, $KOH $and $CH_ {3} COOK $can be written separately in ionic form, and $CH_ {3} COOH $and $H_ {2} O $retain the chemical formula, that is, $CH_ {3} COOH + K ^{+} + O H ^{-} = CH_ {3} C O O ^{-} + K ^{+} + H_ {2} O $.

The same $K ^ {+} $on both sides can be deleted, resulting in a net ionic equation for the reaction of acetic acid with potassium hydroxide of $CH_ {3} COOH + OH ^{-} = CH_ {3} COO ^{-} + H_ {2} O $. This formula accurately reflects the essence of the reaction, that is, acetic acid molecules react with hydroxide ions to form acetate ions and water.