The molecular weight of ethyl acetate
The molecular weight (Mw) of ethyl acetate requires detailed investigation of its constituent elements and atomic numbers. The chemical formula of ethyl acetate is $C_ {4} H_ {8} O_ {2} $.

Carbon (C) has an atomic weight of about 12; hydrogen (H) has an atomic weight of about 1; oxygen (O) has an atomic weight of about 16.

The chemical formula of ethyl acetate contains four atoms of carbon, eight atoms of hydrogen, and diatoms of oxygen. Then its molecular weight (Mw) is calculated as follows:

The total atomic weight of carbon is 4 dollars\ times12 = 48 $; the total atomic weight of hydrogen is 8 dollars\ times1 = 8 $; the total atomic weight of oxygen is 2 dollars\ times16 = 32 $.

Add the three, and the molecular weight (Mw) of ethyl acetate is 48 dollars + 8 + 32 = 88 $.

From this, it can be seen that the molecular weight (Mw) of ethyl acetate is exactly 88. This value is of great significance in many chemical studies and practical applications. It is also a key parameter for the calculation of related chemical reactions.