On the molecular weight of anhydrous sodium acetate
The nature of the research substance must be investigated. Anhydrous sodium acetate is a common product in chemistry, and the study of its molecular weight is essential for all uses.

The formula of sodium acetate is\ (C_ {2} H_ {3} NaO_ {2}\). To know the molecular weight of anhydrous sodium acetate, when the atomic weight of each. The atomic weight of carbon (\ (C\)) is about\ (12\), the atomic weight of hydrogen (\ (H\)) is about\ (1\), the atomic weight of sodium (\ (Na\)) is about\ (23\), and the atomic weight of oxygen (\ (O\)) is about\ (16\).

In anhydrous sodium acetate\ (C_ {2} H_ {3} NaO_ {2}\), there are two carbon, three hydrogen, one sodium, and two oxygen. Calculate its molecular weight according to the following method: the atomic weight of carbon two is\ (2\ times12 = 24\); the atomic weight of hydrogen is\ (3\ times1 = 3\); the atomic weight of sodium one is\ (23\); the atomic weight of oxygen two is\ (2\ times16 = 32\).

If the sum of the atomic weights is combined, the molecular weight of anhydrous sodium acetate is\ (24 + 3 + 23 + 32 = 82\).

From the perspective of experiments, the value of this molecular weight is related to the calculation of the quality and quantity of the substance. The preparation of the solution and the determination of its concentration depend on this number. In the chemical industry, the calculation of materials is also based on this. Therefore, the study of the molecular weight of anhydrous sodium acetate is essential in the field of chemistry and industry.