"On the Molecular Weight of Barium Acetate"

To study the molecular weight of barium acetate, we should use scientific methods to investigate its constituent elements and atomic quantities in detail. The chemical formula of barium acetate is $Ba (CH_3COO) _2 $, which is composed of barium ($Ba $), carbon ($C $), hydrogen ($H $), and oxygen ($O $).

The relative atomic mass of barium is about 137, the relative atomic mass of carbon is about 12, the relative atomic mass of hydrogen is about 1, and the relative atomic mass of oxygen is about 16. In $Ba (CH_3COO) _2 $, barium atoms have 1; carbon atoms, because acetate has 2, each acetate contains 2 carbons, so the total number of carbon atoms is 2 dollars\ times2 = 4 $; hydrogen atoms, each acetate contains 3 hydrogen, a total of 2 dollars\ times3 = 6 $; oxygen atoms, each acetate contains 2 oxygen, a total of 2 dollars\ times2 = 4 $.

According to the method of molecular weight calculation, the molecular weight of barium acetate is: the atomic weight of barium + the sum of the atomic weight of carbon + the sum of the atomic weight of hydrogen + the sum of the atomic weight of oxygen, that is, 137 dollars + 12\ times4 + 1\ times6 + 16\ times4 $
$= 137 + 48 + 6 + 64 $
$= 255 $.

Therefore, the molecular weight of barium acetate is 255, which is obtained by accurate calculation. It is of great significance for chemical research and experiments.