The molecular weight of aluminum acetate is calculated today. For aluminum acetate, the formula is $Al (CH_ {3} COO) _ {3} $. To know its molecular weight, it is necessary to know the atomic weight of each atom. The atomic weight of aluminum ($Al $) is about 27 dollars $, the atomic weight of carbon ($C $) is about 12 dollars $, the atomic weight of hydrogen ($H $) is about 1 dollar $, and the atomic weight of oxygen ($O $) is about 16 dollars $.

In aluminum acetate $Al (CH_ {3} COO) _ {3} $, aluminum atoms have 1 dollar $, and their contribution atomic weight is 27 dollars\ times1 = 27 $; carbon atoms have 3 dollars\ times2 = 6 $, and their contribution atomic weight is 12 dollars\ times6 = 72 $; hydrogen atoms have 3 dollars\ times3 = 9 $, and their contribution atomic weight is 1 dollar\ times9 = 9 $; oxygen atoms have 3 dollars\ times2 = 6 $, and their contribution atomic weight is 16 dollars\ times6 = 96 $.

The molecular weight of aluminum acetate is obtained by adding the atomic weights contributed by each atom: 27 dollars + 72 + 9 + 96 = 204 dollars.

Therefore, the molecular weight of aluminum acetate is 204 dollars $.