"Calculating the molar mass of lead (ⅱ) acetate"

To know the molar mass of lead (ⅱ) acetate, it is necessary to know its composition and atomic weight of each element. The chemical formula of lead (ⅱ) acetate is $Pb (CH_ {3} COO) _ {2} $.

Lead ($Pb $) has an atomic weight of about 207.2. The atomic weight of carbon ($C $) is about 12.01, and there are two carbon atoms in acetate, so the total contribution of carbon is 12.01 dollars\ times 4 = 48.04 $. Hydrogen ($H $) has an atomic weight of about 1.01 dollars\ times 6 = 6.06 $. The atomic weight of oxygen ($O $) is about 16.00, there are four oxygen atoms in acetate, and the contribution of oxygen is 16 dollars\ times 4 = 64.00 $.

Then the molar mass of lead (ⅱ) acetate is: 207.2 dollars + 48.04 + 6.06 + 64.00 = 325.3 $ ($g/mol $). In summary, the molar mass of lead (ⅱ) acetate is about 325.3 $g/mol $.