The chemical equation for the reaction of lead acetate and potassium chromate
There are currently lead acetate ($Pb (CH_ {3} COO) _ {2} $) combined with potassium chromate ($K_ {2} CrO_ {4} $) to obtain the chemical equation for the reaction.

Lead acetate can be dissociated into lead ions ($Pb ^ {2 +} $) and acetate ions ($CH_ {3} COO ^{-}$）， potassium chromate in solution to dissociate into potassium ions ($K ^ {+} $) and chromate ions ($CrO_ {4} ^ {2 - }$）。

When the two meet, lead ions combine with chromate ions to form a precipitation of lead chromate ($PbCrO_ {4} $), and acetate ions and potassium ions remain in the solution to form potassium acetate ($CH_ {3} COOK $).

The chemical reaction equation is initially written as: $Pb (CH_ {3} COO) _ {2} + K_ {2} CrO_ {4}\ longrightarrow PbCrO_ {4} + CH_ {3} COOK $

However, this formula has not yet been balanced, observe the number of atoms, there are 2 dollars $acetate ions on the left, and only 1 dollar $on the right, so before the $CH_ {3} COOK $with 2 dollars $, so that the number of acetate ions is equal.

The chemical equation after balancing is: $Pb (CH_ {3} COO) _ {2} + K_ {2} CrO_ {4} = PbCrO_ {4}\ downarrow + 2CH_ {3} COOK $

In this way, the chemical equation for the reaction of lead acetate and potassium chromate is completed, and the number of atoms before and after the reaction is conserved, which is consistent with the law of chemical change.