"On the Molar Mass of Lead (ⅱ) Acetate"

Now I want to study the molar mass of lead (ⅱ) acetate. The chemical formula of lead (ⅱ) acetate is $Pb (CH_3COO) _2 $. To know its molar mass, it is necessary to know the relative atomic mass of each element. The relative atomic mass of lead ($Pb $) is about 207.2 dollars $, carbon ($C $) is about 12.01 dollars $, hydrogen ($H $) is about 1.01 dollars $, and oxygen ($O $) is about 16 dollars $.

In $Pb (CH_3COO) _2 $, the lead atom has one, and its corresponding mass is 207.2 dollars $; the carbon atom has four, and the mass is 4 dollars\ times12.01 = 48.04 $; the hydrogen atom has six, and the mass is 6 dollars\ times1.01 = 6.06 $; the oxygen atom has four, and the mass is 4 dollars\ times16.00 = 64.00 $.

Add the masses of the atoms, and the molar mass of lead (II) acetate is: 207.2 dollars + 48.04 + 6.06 + 64.00 = 325.3 $ ($g/mol $). It can be seen that the molar mass of lead (ⅱ) acetate is about $325.3g/mol $, which is very important in chemical calculations and related studies, and can help to accurately grasp the proportion of substances and chemical reactions.