On the Molecular Formula of Ethyl Acetate
The molecular formula weight of ethyl acetate ($C_4H_8O_2 $) should be based on the atomic weight of the elements. The atomic weight of carbon ($C $) is about 12, the atomic weight of hydrogen ($H $) is about 1, and the atomic weight of oxygen ($O $) is about 16.

The molecular formula of ethyl acetate contains carbon 4, hydrogen 8, and oxygen 2. According to the method of molecular formula weight, that is, the sum of the product of each atomic weight and its atomic number.

The carbon part, 4 dollars $of carbon atoms, contributes 4 dollars\ times12 = 48 $; the hydrogen part, 8 dollars $of hydrogen atoms, contributes 8 dollars\ times1 = 8 $; the oxygen part, 2 dollars $of oxygen atoms, contributes 2 dollars\ times16 = 32 $.

Add these three parts together, 48 dollars + 8 + 32 = 88 $, so the molecular formula of ethyl acetate is 88. This value is of great significance in many fields of chemistry, such as reaction measurement, material purity consideration, etc., and can help to analyze the reaction relationship between substances and the amount of content.