The method of making ethyl acetate from bromoethane
Now we want to start with bromoethane to prepare ethyl acetate. First, bromoethane is heated with an alcohol solution of potassium hydroxide, and a digestion reaction occurs. Bromoethane dehydrogenates to obtain ethylene. The reaction formula is: $C_ {2} H_ {5} Br + KOH (alcohol) \ stackrel {\ Delta }{=\!=\!=} CH_ {2} = CH_ {2}\ uparrow + KBr + H_ {2} O $.

Then, ethylene and water are heated and pressurized in the presence of a catalyst, and an addition reaction occurs. Ethylene and water combine to form ethanol. The reaction formula is: $CH_ {2} = CH_ {2} + H_ {2} O\ stackrel {catalyst} {\ underset {heat, pressure }{=\!=\!=}} C_ {2} H_ {5} OH $.

Then the obtained ethanol is co-heated with oxygen using copper or silver as a catalyst, and the ethanol undergoes catalytic oxidation to form acetaldehyde, which is then oxidized to acetic acid. The reaction formula is that ethanol is oxidized to acetaldehyde: $2C_ {2} H_ {5} OH + O_ {2}\ stackrel {Cu or Ag} {\ underset {\ Delta }{=\!=\! =}} 2CH_ {3} CHO + 2H_ {2} O $; acetaldehyde is oxidized to acetic acid: $2CH_ {3} CHO + O_ {2}\ stackrel {catalyst} {\ underset {\ Delta }{=\!=\!=}} 2CH_ {3} COOH $.

Finally, ethanol and acetic acid are esterified under the condition of concentrated sulfuric acid as a catalyst and heating to form ethyl acetate and water. The reaction formula is: $CH_ {3} COOH + C_ {2} H_ {5} OH\ underset {\ Delta} {\ overset {concentrated sulfuric acid} {\ rightleftharpoons}} CH_ {3} COOC_ {2} H_ {5} + H_ {2} O $. According to this step, ethyl acetate can be prepared from bromoethane.