Ethyl acetate, its molecular formula is $C_ {4} H_ {8} O_ {2} $. To find its simplest expression, you need to find the simplest integer ratio of the atomic number of each element.

The atomic number ratio of $C $, $H $, $O $is 4 dollars: 8:2 $. Simplify it and divide the items by 2 dollars $at the same time to get the simplest integer ratio of 2 dollars: 4:1 $.

Therefore, the simplest expression of ethyl acetate is $C_ {2} H_ {4} O $.

The molecular formula of ethyl acetate is $C_ {4} H_ {8} O_ {2} $. To find its empirical formula, we need to find the simplest whole - number ratio of the atoms of each element.

The ratio of the numbers of $C $, $H $, and $O $atoms is 4 dollars: 8:2 $. Simplifying this ratio by dividing each term by 2, we get the simplest whole - number ratio of 2 dollars: 4:1 $.

So, the empirical formula of ethyl acetate is $C_ {2} H_ {4} O $.