The ionic equation for the reaction between acetic acid ($CH_3COOH $) and potassium hydroxide ($KOH $) is the core of classical Chinese as follows:

"On the Response between Acid and Base"

Now there is acetic acid, weak acid is also mild in nature. Potassium hydroxide, a strong base, is strong in nature. When the two meet, there will be a reaction.

Acetic acid in water is less isolated and weakly acidic, and its formula is $CH_3COOH\ rightleftharpoons CH_3COO ^ - + H ^ + $. When potassium hydroxide enters water, it is completely separated into potassium ion ($K ^ + $) and hydroxide ion ($OH ^ - $), that is, $KOH = K ^ ++ OH ^ - $.

When the two are mixed, the hydrogen ion separated by acetic acid ($H ^ + $) and the hydroxide ion separated by potassium hydroxide ($OH ^ - $) quickly combine into water, $H ^ ++ OH ^ - = H_2O $. The acetate ion ($CH_3COO ^ - $) and potassium ion ($K ^ + $) still exist in the liquid without changing their properties.

So the net ionic equation for the reaction of acetic acid and potassium hydroxide is: $CH_3COOH + OH ^ - = CH_3COO ^ - + H_2O $. This formula is also simple and clear, showing the essence of the reaction between the two, that is, the combination of hydrogen ions and hydroxide ions, and acetic acid participates in the state of molecules, which is different from the reaction of strong electrolytes.